Ammonium carbamate dissociates as NH 2 COONH 4( s ) leftharpoons 2 NH 3( g )+ CO 2( g ) In a closed vessel containing ammonium carbamate in equilibrium, ammonia is added such that partial pressure of NH 3 now equals to the original total pressure. Calculate the ratio of partial pressure of CO 2 now to the original partial pressure of CO 2

Question

Ammonium carbamate dissociates as NH 2 COONH 4( s ) leftharpoons 2 NH 3( g )+ CO 2( g ) In a closed vessel containing ammonium carbamate in equilibrium, ammonia is added such that partial pressure of NH 3 now equals to the original total pressure. Calculate the ratio of partial pressure of CO 2 now to the original partial pressure of CO 2 (A) 4 (B) 9 (C) (4/9) (D) (2/9)

Tardigrade Admin · Accepted Answer

NH 2 COONH 4( s ) leftharpoons 2 NH 3( g )+ CO 2( g ) Let partial pressure at equilibrium of CO 2 be P, then P NH 3=2 P and total pressure at Equilibrium =3 P KP=(2 P)2 × P=4 P 3...(1) If NH 3 is added and the pressure of NH 3 after addition at equilibrium is 3 P KP=4 P3=(P NH 3')2 × P CO 2' ⇒ P CO 2'=(4/9) P ∴ ratio of (P CO 2'/P CO 2)=(4/9)

4

9

$\frac{4}{9}$

$\frac{2}{9}$

4

9

94​

92​

$\frac{4}{9}$

$\frac{2}{9}$