1. Tardigrade
  2. Question
  3. Chemistry
  4. Ammonium carbamate dissociates as NH 2 COONH 4( s ) leftharpoons 2 NH 3( g )+ CO 2( g ) In a closed vessel containing ammonium carbamate in equilibrium, ammonia is added such that partial pressure of NH 3 now equals to the original total pressure. Calculate the ratio of partial pressure of CO 2 now to the original partial pressure of CO 2

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Q. Ammonium carbamate dissociates as
$NH _{2} COONH _{4}( s ) \rightleftharpoons 2 NH _{3}( g )+ CO _{2}( g )$
In a closed vessel containing ammonium carbamate in equilibrium, ammonia is added such that partial pressure of $NH _{3}$ now equals to the original total pressure. Calculate the ratio of partial pressure of $CO _{2}$ now to the original partial pressure of $CO _{2}$

Equilibrium

Solution:

$NH _{2} COONH _{4}( s ) \rightleftharpoons 2 NH _{3}( g )+ CO _{2}( g )$ Let partial pressure

at equilibrium of $CO _{2}$ be $P$, then $P_{ NH _{3}}=2 P$ and total pressure at Equilibrium $=3 P$

$K_{P}=(2 P)^{2} \times P=4 P ^{3}$...(1)

If $NH _{3}$ is added and the pressure of $NH _{3}$ after addition at equilibrium is $3 P$

$K_{P}=4 P^{3}=\left(P_{ NH _{3}}'\right)^{2} \times P_{ CO _{2}}'$

$\Rightarrow P_{ CO _{2}}'=\frac{4}{9} P$

$\therefore $ ratio of $\frac{P_{ CO _{2}}'}{P_{ CO _{2}}}=\frac{4}{9}$