Question

Aluminium phosphate is $100\%$ ionised in $0.01$ molal aqueous solution. Hence, $\Delta T_b/K_b$ is:

• A. $0.01$
• B. $0.015$
• C. $0.0175$
• D. $0.02$

Answer 1

Answer: (D)

$AIP{O}_4\rightleftharpoons A{l}^{3+}+P{O}_4^{3-}$
$i=1+x=2$
$\Delta T_b=i\times K_b\times m$
$\therefore \frac{\Delta T_b}{K_b}=0.02$