Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. Aluminium phosphate is $100\%$ ionised in $0.01$ molal aqueous solution. Hence, $\Delta\,T_{b}/K_{b}$ is:

Solutions

Solution:

$AIPO_{4} \rightleftharpoons Al^{3+}+PO^{3-}_{4}$
$i=1+x=2$
$\Delta\,T_{b} =i \times K_{b} \times m$
$\therefore \frac{\Delta T_{b}}{K_{b}}=0.02$