Q.
All the points of discontinuity of the function f defined by f(x)=⎩⎨⎧345if 0<x<1if 1<x<3areif 3≤x≤10
2126
180
Continuity and Differentiability
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Solution:
f(x)=⎩⎨⎧345if 0<x<1if 1<x<3if 3≤x≤10
For 0≤x≤1,f(x)=3;1<x<3;f(x)=4 and 3≤x≤10,f(x)=5 are constant functions, so it is continuous in the above interval,
so we have to check the continuity at x=1,3
At x=1, LHL =x→1−limf(x)=x→1−lim(3)=3 RHI=x→1+limf(x)=x→1+lim(4)=4 ∴LHL=RHL
Thus, f(x) is discontinuous at x=1
At x=3,LHL=x→3−limf(x)=x→3−lim(4)=4 RHL=x→3+limf(x)=x→3+lim(5)=5 ∴LHL=RHL
Thus, f(x) is continuous everywhere except at x=1,3