All the edges of a block with parallel faces are unequal. Its largest edge is twice its shortest edge. The ratio of the maximum to the minimum resistance between parallel faces is

Question

All the edges of a block with parallel faces are unequal. Its largest edge is twice its shortest edge. The ratio of the maximum to the minimum resistance between parallel faces is (A) 8 (B) 4 (C) 2 (D) 1

Tardigrade Admin · Accepted Answer

Let the length of various edges in increasing order be l,x,2l respectively Rm a x=(ρ 2 l/x l)=(2 ρ /x);Rm i n=(ρ l/2 l x)=(ρ /2 x) ∴ (Rm a x/Rm i n)=4

Q. All the edges of a block with parallel faces are unequal. Its largest edge is twice its shortest edge. The ratio of the maximum to the minimum resistance between parallel faces is

$8$

$4$

$2$

$1$

Let the length of various edges in increasing order be $l, x, 2 l$ respectively
$R_{ma x} = \frac{ρ 2 l}{x l} = \frac{2 ρ}{x}; R_{min} = \frac{ρl}{2 l x} = \frac{ρ}{2 x}$
$∴ \frac{R _{ma x}}{R _{min}} = 4$

Q. All the edges of a block with parallel faces are unequal. Its largest edge is twice its shortest edge. The ratio of the maximum to the minimum resistance between parallel faces is

8

4

2

1

Let the length of various edges in increasing order be l,x,2l respectively Rmax​=xlρ2l​=x2ρ​;Rmin​=2lxρl​=2xρ​ ∴Rmin​Rmax​​=4

$8$

$4$

$2$

$1$

Let the length of various edges in increasing order be $l, x, 2 l$ respectively
$R_{ma x} = \frac{ρ 2 l}{x l} = \frac{2 ρ}{x}; R_{min} = \frac{ρl}{2 l x} = \frac{ρ}{2 x}$
$∴ \frac{R _{ma x}}{R _{min}} = 4$