Question

All six capacitors shown are identical. Each can withstand maximum 200 volts between its terminals. The maximum voltage that can be safely applied between $A$ and $B$ is

• A. 1200 V
• B. 400 V
• C. 800 V
• D. 200 V

Answer 1

Answer: (B)

Given circuit can be reduced as follows

$(C=$ capacitance of each capacitor $)$
The capacitors $(3C,3C)$ shown in figure can withstand maximum $200V$ individually.
$\therefore$ So maximum voltage that can be applied across $A$ and $B$ is equally shared. Hence, maximum voltage applied across $A$ and $B$ will be $(200+200)=400$ volt.