Alkyl halides can be obtained by all methods except:

Question

Alkyl halides can be obtained by all methods except: (A) CH 3- CH 2- CH 2- CH 3+ Cl 2 ( UV / text light ) (B) CH 3 CH 2 OH + HCl / ZnCl 2 stackrelΔ longrightarrow (C) C 2 H 2 OH + NaCl arrow (D) CH 3 COOAg + Br 2 stackrel CCl 4 longrightarrow

Tardigrade Admin · Accepted Answer

OH- is a poor leaving group. So, it can not be substituted directly.

Q. Alkyl halides can be obtained by all methods except:

$C H_{3} - C H_{2} - C H_{2} - C H_{3} + C l_{2} \frac{U V}{light}$

$C H_{3} C H_{2} O H + H Cl / Z n C l_{2} ⟶ Δ$

$C_{2} H_{2} O H + N a Cl \to$

$C H_{3} COO A g + B r_{2} ⟶ CC l_{4}$

$O H^{-}$ is a poor leaving group. So, it can not be substituted directly.

Q. Alkyl halides can be obtained by all methods except:

CH3​−CH2​−CH2​−CH3​+Cl2​ light UV​

CH3​CH2​OH+HCl/ZnCl2​⟶Δ​

C2​H2​OH+NaCl→

CH3​COOAg+Br2​⟶CCl4​​

OH− is a poor leaving group. So, it can not be substituted directly.

$C H_{3} - C H_{2} - C H_{2} - C H_{3} + C l_{2} \frac{U V}{light}$

$C H_{3} C H_{2} O H + H Cl / Z n C l_{2} ⟶ Δ$

$C_{2} H_{2} O H + N a Cl \to$

$C H_{3} COO A g + B r_{2} ⟶ CC l_{4}$

$O H^{-}$ is a poor leaving group. So, it can not be substituted directly.