Question

Alkyl halides can be obtained by all methods except:

• A. $CH _{3}- CH _{2}- CH _{2}- CH _{3}+ Cl _{2} \frac{ UV }{\text { light }}$
• B. $CH _{3} CH _{2} OH + HCl / ZnCl _{2} \stackrel{\Delta}{\longrightarrow}$
• C. $C _{2} H _{2} OH + NaCl \rightarrow$
• D. $CH _{3} COOAg + Br _{2} \stackrel{ CCl _{4}}{\longrightarrow}$

Answer 1

Answer: (C)

$OH^{-}$ is a poor leaving group. So, it can not be substituted directly.