A l (at. wt 27 ) crystallizes in the cubic system with a cell edge of 4.05 mathringA. Its density is 2.7 g per cm 3. Determine the unit cell type calculate the radius of the Al atom

Question

A l (at. wt 27 ) crystallizes in the cubic system with a cell edge of 4.05 mathringA. Its density is 2.7 g per cm 3. Determine the unit cell type calculate the radius of the Al atom (A) fcc, 2.432 mathringA (B) bcc, 2.432 mathringA (C) bcc, 1.432 mathringA (D) fcc, 1.432 mathringA

Tardigrade Admin · Accepted Answer

ρ=(Z × M/No × a3) 2.7=(Z × 27/6.02 × 1023 ×(4.05)3 × 10-24) ∴ Z=4 Hence it is face centered cubic unit lattice Again 4 r=a √2=5.727 mathringA

Q. $A l$ (at. wt $27$ ) crystallizes in the cubic system with a cell edge of $4.05 \overset{˚}{A}$ . Its density is $2.7 g$ per $c m^{3}$ . Determine the unit cell type calculate the radius of the $A l$ atom

fcc, $2.432 \overset{˚}{A}$

bcc, $2.432 \overset{˚}{A}$

bcc, $1.432 \overset{˚}{A}$

fcc, $1.432 \overset{˚}{A}$

$ρ = \frac{Z \times M}{N _{o} \times a ^{3}}$
$2.7 = \frac{Z \times 27}{6.02 \times 1 0 ^{23} \times ( 4.05 ) ^{3} \times 1 0 ^{- 24}}$
$∴ Z = 4$
Hence it is face centered cubic unit lattice
Again $4 r = a 2 = 5.727 \overset{˚}{A}$

Q. Al (at. wt 27 ) crystallizes in the cubic system with a cell edge of 4.05A˚. Its density is 2.7g per cm3. Determine the unit cell type calculate the radius of the Al atom

fcc, 2.432A˚

bcc, 2.432A˚

bcc, 1.432A˚

fcc, 1.432A˚