Question

$a{K}_{2}C{r}_2{O}_7+bKCl+c{H}_{2}S{O}_4⟶xCr{O}_{2}C{l}_2+yKHS{O}_4+z{H}_{2}O$
The above equation balances when

• A. a = 2, b = 4, c = 6 and x = 2, y = 6, z = 3
• B. a = 4, b = 2, c = 6 and x = 6, y = 2, z = 3
• C. a = 6, b = 4, c = 2 and x = 6, y = 3, z = 2
• D. a = 1, b = 4, c = 6 and x = 2, y = 6, z = 3

Answer 1

Answer: (D)

Here, $K_{2}C{r}_2{O}_7$ acts as a oxidizing agent.
Basically, Hydrogen and oxygen atoms are balanced on both sides of the equation.
The balanced equation is :
$K_{2}C{r}_2{O}_7+4KCl+6H_{2}S{O}_4=2Cr{O}_{2}C{l}_2+6KHS{O}_4+3H_{2}O$
It is a redox reaction. After complete balance equation, the values of variables are:
$a=1,b=4,c=6,x=2,y=6,z=3$.