Air is filled in a bottle at atmospheric pressure and it is corked at 35 ° C . If the cork can come out at a pressure 3 times the atmospheric pressure, then up to what temperature should the bottle be heated in order to remove the cork?

Question

Air is filled in a bottle at atmospheric pressure and it is corked at 35 ° C . If the cork can come out at a pressure 3 times the atmospheric pressure, then up to what temperature should the bottle be heated in order to remove the cork? (A) 325.5° C (B) 851° C (C) 651° C (D) None of these

Tardigrade Admin · Accepted Answer

We know that, p1V=nRT1 ⇒ 1× V=nR(35 + 273) =nR× 308 ....(i) and p2V=nRT2 ⇒ 3× V=nRT2 ....(ii) On dividing Equation (ii) by Equation (i), we get 3=T2 / 308 ⇒ T2=924 K T2=924-273 =651° C

Q. Air is filled in a bottle at atmospheric pressure and it is corked at $35^{\circ} C$ . If the cork can come out at a pressure $3$ times the atmospheric pressure, then up to what temperature should the bottle be heated in order to remove the cork?

$325. 5^{\circ} C$

$85 1^{\circ} C$

$65 1^{\circ} C$

None of these

Q. Air is filled in a bottle at atmospheric pressure and it is corked at 35∘C . If the cork can come out at a pressure 3 times the atmospheric pressure, then up to what temperature should the bottle be heated in order to remove the cork?

325.5∘C

851∘C

651∘C

None of these

We know that, p1​V=nRT1​ ⇒1×V=nR(35+273) =nR×308 ....(i) and p2​V=nRT2​ ⇒3×V=nRT2​ ....(ii) On dividing Equation (ii) by Equation (i), we get 3=T2​/308 ⇒T2​=924K T2​=924−273 =651∘C

Q. Air is filled in a bottle at atmospheric pressure and it is corked at $35^{\circ} C$ . If the cork can come out at a pressure $3$ times the atmospheric pressure, then up to what temperature should the bottle be heated in order to remove the cork?

$325. 5^{\circ} C$

$85 1^{\circ} C$

$65 1^{\circ} C$