Question

Adsorption of a gas follows Freundlich adsorption isotherm x is the mass of the gas adsorbed on mass m of the adsorbent. The plot of $\log \frac{x}{m}$ versus log p is shown in the given graph. $\frac{x}{m}$ is proportional to :

• A. $p^{3/2}$
• B. $p^3$
• C. $p^{2/3}$
• D. $p^2$

Answer 1

Answer: (C)

$\frac{x}{m}=K.p^{\frac{1}{n}}$
$\therefore \log \frac{x}{m}=\log K+\frac{1}{n}.\log P$
$\text{slope}=\frac{1}{n}=\frac{2}{3}$
$\therefore \frac{x}{m}=K.p^{\frac{2}{3}}$