Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. Adsorption of a gas follows Freundlich adsorption isotherm x is the mass of the gas adsorbed on mass m of the adsorbent. The plot of $\log \frac{x}{m}$ versus log p is shown in the given graph. $\frac{x}{m}$ is proportional to :Chemistry Question Image

JEE MainJEE Main 2019Surface Chemistry

Solution:

$\frac{x}{m} =K.p^{\frac{1}{n}}$
$ \therefore \log \frac{x}{m} = \log K+\frac{1}{n} . \log P $
$ \text{slope} = \frac{1}{n} = \frac{2}{3} $
$ \therefore \frac{x}{m} = K.p^{\frac{2}{3}} $