Additive inverse of 1-i is

Question

Additive inverse of 1-i is (A) 0+0 i (B) -1-i (C) -1+i (D) None of these

Tardigrade Admin · Accepted Answer

If z=x+i y is the additive inverse of 1-i, then (x+i y)+(1-i)=0 ⇒ x+1=0, y-1=0 ⇒ x=-1, y=1 ∴ The additive inverse of 1- i is z =-1+ i Trick: Since (1-i)+(-1+i)=0.

Q. Additive inverse of $1 - i$ is

$0 + 0 i$

$- 1 - i$

$- 1 + i$

None of these

If $z = x + i y$ is the additive inverse of $1 - i$ , then
$(x + i y) + (1 - i) = 0$
$\Rightarrow x + 1 = 0, y - 1 = 0$
$\Rightarrow x = - 1, y = 1$
$∴$ The additive inverse of $1 - i$ is $z = - 1 + i$
Trick: Since $(1 - i) + (- 1 + i) = 0$ .

Q. Additive inverse of 1−i is

0+0i

−1−i

−1+i