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Q.
Additive inverse of $1-i$ is
Complex Numbers and Quadratic Equations
Solution:
If $z=x+i y$ is the additive inverse of $1-i$, then
$(x+i y)+(1-i)=0$
$\Rightarrow x+1=0, y-1=0$
$ \Rightarrow x=-1, y=1$
$\therefore $ The additive inverse of $1- i$ is $z =-1+ i$
Trick: Since $(1-i)+(-1+i)=0$.