Addition of excess of AgNO3 to an aqueous solution of 1 mole of PdCl2. 4NH3 gives 2 moles of AgCl. The conductivity of this solution corresponds to

Question

Addition of excess of AgNO3 to an aqueous solution of 1 mole of PdCl2. 4NH3 gives 2 moles of AgCl. The conductivity of this solution corresponds to (A) 1: 2 electrolyte (B) 1: 4 electrolyte (C) 1: 1 electrolyte (D) 1: 3 electrolyte

Tardigrade Admin · Accepted Answer

[Pb(NH3)4]Cl2 →[Pb(NH3)4]2++2cI- It is 1: 2 i.e., AB2 type of electrolyte.

Q. Addition of excess of AgNO₃ to an aqueous solution of 1 mole of PdCl₂. 4NH₃ gives 2 moles of AgCl. The conductivity of this solution corresponds to

1 : 2 electrolyte

1 : 4 electrolyte

1 : 1 electrolyte

1 : 3 electrolyte

$[P b (N H_{3})_{4}] C l_{2} \to [P b (N H_{3})_{4}]^{2 +} + 2 c I^{-}$
$I t i s 1 : 2 i . e ., A B_{2}$ type of electrolyte.

Q. Addition of excess of AgNO3 to an aqueous solution of 1 mole of PdCl2. 4NH3 gives 2 moles of AgCl. The conductivity of this solution corresponds to