Acetyl bromide reacts with excess of CH3MgI followed by treatment with a saturated solution of NH4Cl gives:

Question

Acetyl bromide reacts with excess of CH3MgI followed by treatment with a saturated solution of NH4Cl gives: (A) Acetyl iodide (B) Acetamide (C) 2-Methyl-2-propanol (D) Acetone

Tardigrade Admin · Accepted Answer

Correct answer is (c) 2-Methyl-2-propanol

Q. Acetyl bromide reacts with excess of CH3​MgI followed by treatment with a saturated solution of NH4​Cl gives:

Acetyl iodide

Acetamide

2-Methyl-2-propanol

Acetone

Correct answer is (c) 2-Methyl-2-propanol

Q. Acetyl bromide reacts with excess of $C H_{3} M g I$ followed by treatment with a saturated solution of $N H_{4} Cl$ gives: