Acetic acid undergoes dimerisation, when dissolved in benzene Molecular mass of acetic acid is found 120. Which among the following relation is correct? D = theroartical vapour density d = observed vapour density

Question

Acetic acid undergoes dimerisation, when dissolved in benzene <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/c-9t97swerhmv4qviy.jpg" /> Molecular mass of acetic acid is found 120. Which among the following relation is correct? D = theroartical vapour density d = observed vapour density (A) α =2((D - d/d)) (B) α =2((D - d/D)) (C) α =2((d - D/d)) (D) α =(2 d/D - d)

Tardigrade Admin · Accepted Answer

Here α =1 Because CH3COOH will have molecualar mass = 120 Due to 100% association n =2 (for dimerisation) For association of molecule α =(d - D/d (1 - (1)n))=(d - D/d (1 - (1)2)) =(2 (. d - D .)/d)

Q. Acetic acid undergoes dimerisation, when dissolved in benzene

Molecular mass of acetic acid is found 120. Which among the following relation is correct?
D = theroartical vapour density
d = observed vapour density

$α = 2 (\frac{D - d}{d})$

$α = 2 (\frac{D - d}{D})$

$α = 2 (\frac{d - D}{d})$

$α = \frac{2 d}{D - d}$

Here $α = 1$
Because $C H_{3} COO H$ will have molecualar mass = 120
Due to 100% association n =2 (for dimerisation)
For association of molecule
$α = \frac{d - D}{d ( 1 - \frac{1}{n} )} = \frac{d - D}{d ( 1 - \frac{1}{2} )}$
$= \frac{2 ( d - D )}{d}$

Q. Acetic acid undergoes dimerisation, when dissolved in benzene Molecular mass of acetic acid is found 120. Which among the following relation is correct? D = theroartical vapour density d = observed vapour density

α=2(dD−d​)

α=2(DD−d​)

α=2(dd−D​)

α=D−d2d​