Acetamide and ethylamine can be distinguished by reacting with

Question

Acetamide and ethylamine can be distinguished by reacting with (A) dilute HCl and heat (B) NaOH solution and heat (C) acidified KMnO4 (D) Br2 water

Tardigrade Admin · Accepted Answer

Acetamide in the presence of NaOH and heat changes to acetic acid while ethylamine does not undergo any reaction. underset text Acetamide CH 3 CONH 2 longrightarrow CH 3 COOH + NH 3 uparrow

Q. Acetamide and ethylamine can be distinguished by reacting with

dilute $H Cl$ and heat

$N a O H$ solution and heat

acidified $K M n O_{4}$

$B r_{2}$ water

Acetamide in the presence of $N a O H$ and heat changes to acetic acid while ethylamine does not undergo any reaction.
$Acetamide C H_{3} CON H_{2} ⟶ C H_{3} COO H + N H_{3} ↑$

Q. Acetamide and ethylamine can be distinguished by reacting with

dilute HCl and heat

NaOH solution and heat

acidified KMnO4​

Br2​ water

Acetamide in the presence of NaOH and heat changes to acetic acid while ethylamine does not undergo any reaction. Acetamide CH3​CONH2​​⟶CH3​COOH+NH3​↑

dilute $H Cl$ and heat

$N a O H$ solution and heat

acidified $K M n O_{4}$

$B r_{2}$ water

Acetamide in the presence of $N a O H$ and heat changes to acetic acid while ethylamine does not undergo any reaction.
$Acetamide C H_{3} CON H_{2} ⟶ C H_{3} COO H + N H_{3} ↑$