Question

According to Newton's second law of motion, resultant force on a particle is in the direction of acceleration of the particle.

Two forces $F_1$ and $F_2$ are acting on a particle as shown in the figure. The acceleration of the particle is along $X$-axis. The value of $F_1$ (in newton) is ____

Answer 1

Answer: 6

Since, acceleration of particle is along $X$-axis.
So, net forces will be along $X$-axis.
Hence, $\sum F_Y=0$
$\therefore F_2\sin 37^{\circ }-F_1\sin 30^{\circ }=0$
or $\frac{3}{5}{F}_2=\frac{F_1}{2}$
$\therefore F_1=\frac{6}{5}\times 5=6N$