According to Moseleys law, the frequency v of the K α line and the atomic number Z of the element have the relation:

Question

According to Moseleys law, the frequency v of the K α line and the atomic number Z of the element have the relation: (A)  v α ( Z-b )  (B)  v α ( Z-b )2  (C)  √v α ( Z-b )2  (D)  v α (1/( Z-b )2)

Tardigrade Admin · Accepted Answer

According to Moseley the frequency of emitted radiation corresponding to the transition of electron from energy level n2 to n1 is v=R(Z-b)2( (1/n12)-(1/n22) ) ⇒ v propto (Z-b)2 or √v propto (Z-b)

Q. According to Moseleys law, the frequency v of the K $α$ line and the atomic number Z of the element have the relation:

$v α (Z - b)$

$v α (Z - b)^{2}$

$v α (Z - b)^{2}$

$v α \frac{1}{( Z - b ) ^{2}}$

According to Moseley the frequency of emitted radiation corresponding to the transition of electron from energy level $n_{2}$ to $n_{1}$ is $v = R (Z - b)^{2} (\frac{1}{n _{1}^{2}} - \frac{1}{n _{2}^{2}})$ $\Rightarrow$ $v \propto (Z - b)^{2}$ or $v \propto (Z - b)$

Q. According to Moseleys law, the frequency v of the K α line and the atomic number Z of the element have the relation:

vα(Z−b)

vα(Z−b)2

v​α(Z−b)2

vα(Z−b)21​

According to Moseley the frequency of emitted radiation corresponding to the transition of electron from energy level n2​ to n1​ is v=R(Z−b)2(n12​1​−n22​1​) ⇒ v∝(Z−b)2 or v​∝(Z−b)

Q. According to Moseleys law, the frequency v of the K $α$ line and the atomic number Z of the element have the relation:

$v α (Z - b)$

$v α (Z - b)^{2}$

$v α (Z - b)^{2}$

$v α \frac{1}{( Z - b ) ^{2}}$

According to Moseley the frequency of emitted radiation corresponding to the transition of electron from energy level $n_{2}$ to $n_{1}$ is $v = R (Z - b)^{2} (\frac{1}{n _{1}^{2}} - \frac{1}{n _{2}^{2}})$ $\Rightarrow$ $v \propto (Z - b)^{2}$ or $v \propto (Z - b)$