According to MO theory which of the following lists ranks the nitrogen species in terms of increasing bond order :

Question

According to MO theory which of the following lists ranks the nitrogen species in terms of increasing bond order : (A) N2- < N2 < N22- (B) N22- < N2- < N2 (C) N2 < N22- < N2- (D) N2- < N22- < N2

Tardigrade Admin · Accepted Answer

Let us calculate the bond order of all the ions and molecules.
We know that
Bond order

= \frac{no. of bond pairs - no. of anti bonding pairs}{2}

For

N_{2}^{2 -}

Bond order

= \frac{10 - 6}{2} = 2

For

N_{2}^{-}

Bond order

= \frac{10 - 5}{2} = 2.5

For

N_{2}

Bond order

= \frac{10 - 4}{2} = 3

Q. According to MO theory which of the following lists ranks the nitrogen species in terms of increasing bond order :

$N_{2}^{-} < N_{2} < N_{2}^{2 -}$

$N_{2}^{2 -} < N_{2}^{-} < N_{2}$

$N_{2} < N_{2}^{2 -} < N_{2}^{-}$

$N_{2}^{-} < N_{2}^{2 -} < N_{2}$

Q. According to MO theory which of the following lists ranks the nitrogen species in terms of increasing bond order :

N2−​<N2​<N22−​

N22−​<N2−​<N2​

N2​<N22−​<N2−​

N2−​<N22−​<N2​

Let us calculate the bond order of all the ions and molecules. We know that Bond order =2 no. of bond pairs − no. of anti bonding pairs ​ For N22−​ Bond order =210−6​=2 For N2−​ Bond order =210−5​=2.5 For N2​ Bond order =210−4​=3

$N_{2}^{-} < N_{2} < N_{2}^{2 -}$

$N_{2}^{2 -} < N_{2}^{-} < N_{2}$

$N_{2} < N_{2}^{2 -} < N_{2}^{-}$

$N_{2}^{-} < N_{2}^{2 -} < N_{2}$