According to law of equipartition of energy the molar specific heat of a diatomic gas at constant volume where the molecule has one additional vibrational mode is:-

Question

According to law of equipartition of energy the molar specific heat of a diatomic gas at constant volume where the molecule has one additional vibrational mode is:- (A) (3/2) R (B) (7/2) R (C) (9/2) R (D) (5/2) R

Tardigrade Admin · Accepted Answer

Diatomic gas molecules have three translational degree of freedom, two rotational degree of freedom & it is given that it has one vibrational mode so there are two additional degree of freedom corresponding to one vibrational mode, so total degree of freedom

= 7

C_{v} = \frac{f R}{2} = \frac{7 R}{2}

Q. According to law of equipartition of energy the molar specific heat of a diatomic gas at constant volume where the molecule has one additional vibrational mode is:-

$\frac{3}{2} R$

$\frac{7}{2} R$

$\frac{9}{2} R$

$\frac{5}{2} R$

Q. According to law of equipartition of energy the molar specific heat of a diatomic gas at constant volume where the molecule has one additional vibrational mode is:-

23​R

27​R

29​R

25​R

Diatomic gas molecules have three translational degree of freedom, two rotational degree of freedom & it is given that it has one vibrational mode so there are two additional degree of freedom corresponding to one vibrational mode, so total degree of freedom =7 Cv​=2fR​=27R​

$\frac{3}{2} R$

$\frac{7}{2} R$

$\frac{9}{2} R$

$\frac{5}{2} R$