According to kepler's second law, line joining the planet to the sun sweeps out equal areas in equal time intervals. This suggests that for the planet

Question

According to kepler's second law, line joining the planet to the sun sweeps out equal areas in equal time intervals. This suggests that for the planet (A) Radial acceleration is zero (B) Tangential acceleration is zero (C) Transverse acceleration is zero (D) All

Tardigrade Admin · Accepted Answer

By Kepler's second law, ( d A / dt )=( L /2 m ), L is constant, mvr = constant (in its orbit) But since r changes, v also changes and have tangential acceleration also changes. So,transverse acceleration will be zero as the motion is planar.

Q. According to kepler's second law, line joining the planet to the sun sweeps out equal areas in equal time intervals. This suggests that for the planet

Radial acceleration is zero

Tangential acceleration is zero

Transverse acceleration is zero

All

By Kepler's second law,
$\frac{d A}{d t} = \frac{L}{2 m}, L$ is constant, $m v r =$ constant (in its orbit)
But since r changes, v also changes and have tangential acceleration also changes.
So,transverse acceleration will be zero as the motion is planar.

Q. According to kepler's second law, line joining the planet to the sun sweeps out equal areas in equal time intervals. This suggests that for the planet

Radial acceleration is zero

Tangential acceleration is zero

Transverse acceleration is zero

All

By Kepler's second law, dtdA​=2mL​,L is constant, mvr= constant (in its orbit) But since r changes, v also changes and have tangential acceleration also changes. So,transverse acceleration will be zero as the motion is planar.

By Kepler's second law,
$\frac{d A}{d t} = \frac{L}{2 m}, L$ is constant, $m v r =$ constant (in its orbit)
But since r changes, v also changes and have tangential acceleration also changes.
So,transverse acceleration will be zero as the motion is planar.