According to Joule's law, if the potential difference across a conductor having a material of specific resistance remains constant, then the heat produced in the conductor is directly proportional to

Question

According to Joule's law, if the potential difference across a conductor having a material of specific resistance remains constant, then the heat produced in the conductor is directly proportional to (A) ρ (B) ρ2 (C) (1/√ρ) (D) (1/ρ)

Tardigrade Admin · Accepted Answer

P=(V2/R) but R=(ρ l/A) ⇒ P=(V2/ρ l / A)=(A V2/ρ l) . Since (A V2/l) is constant as per given conditions so P propto (1/ρ).

Q. According to Joule's law, if the potential difference across a conductor having a material of specific resistance remains constant, then the heat produced in the conductor is directly proportional to

$ρ$

$ρ^{2}$

$\frac{1}{ρ}$

$\frac{1}{ρ}$

$P = \frac{V ^{2}}{R}$ but $R = \frac{ρl}{A}$
$\Rightarrow P = \frac{V ^{2}}{ρl / A} = \frac{A V ^{2}}{ρl} .$ Since $\frac{A V ^{2}}{l}$
is constant as per given conditions so $P \propto \frac{1}{ρ}$ .

Q. According to Joule's law, if the potential difference across a conductor having a material of specific resistance remains constant, then the heat produced in the conductor is directly proportional to

ρ

ρ2

ρ​1​

ρ1​

P=RV2​ but R=Aρl​ ⇒P=ρl/AV2​=ρlAV2​. Since lAV2​ is constant as per given conditions so P∝ρ1​.

$ρ$

$ρ^{2}$

$\frac{1}{ρ}$

$\frac{1}{ρ}$

$P = \frac{V ^{2}}{R}$ but $R = \frac{ρl}{A}$
$\Rightarrow P = \frac{V ^{2}}{ρl / A} = \frac{A V ^{2}}{ρl} .$ Since $\frac{A V ^{2}}{l}$
is constant as per given conditions so $P \propto \frac{1}{ρ}$ .