According to Heisenberg's uncertainty principle, the product of uncertainties in position and velocities for an electron of mass 9.1× 10-31 kg is:

Question

According to Heisenberg's uncertainty principle, the product of uncertainties in position and velocities for an electron of mass 9.1× 10-31 kg is: (A)  2.8× 10-3 m2 s-1  (B)  3.8× 10-5 m2 s-1  (C)  5.8× 10-5 m2 s-1  (D)  6.8× 10-6 m2 s-1

Tardigrade Admin · Accepted Answer

We will use formula Δ x × Δ p=(h/4 π) to solve problem. Δ x × Δ p=(h/4 π) Δ x × m Δ v=(h/4 π) Δ x × Δ v=(h/4 π m) Δ x= uncertainty in position Δ v= uncertainty in velocity h= Planck's constant =6.63 × 10-34 kg m 2 s -1 m= mass of electron =9.1 × 10-31 kg ∴ Δ x × Δ v=(6.63 × 10-34/4 × 3.14 × 9.1 × 10-31) =5.8 × 10-5 m 2 s -1

Q. According to Heisenberg's uncertainty principle, the product of uncertainties in position and velocities for an electron of mass $9.1 \times 10^{- 31} k g$ is:

$2.8 \times 10^{- 3} m^{2} s^{- 1}$

$3.8 \times 10^{- 5} m^{2} s^{- 1}$

$5.8 \times 10^{- 5} m^{2} s^{- 1}$

$6.8 \times 10^{- 6} m^{2} s^{- 1}$

Q. According to Heisenberg's uncertainty principle, the product of uncertainties in position and velocities for an electron of mass 9.1×10−31kg is:

2.8×10−3m2s−1

3.8×10−5m2s−1

5.8×10−5m2s−1

6.8×10−6m2s−1

Q. According to Heisenberg's uncertainty principle, the product of uncertainties in position and velocities for an electron of mass $9.1 \times 10^{- 31} k g$ is:

$2.8 \times 10^{- 3} m^{2} s^{- 1}$

$3.8 \times 10^{- 5} m^{2} s^{- 1}$

$5.8 \times 10^{- 5} m^{2} s^{- 1}$

$6.8 \times 10^{- 6} m^{2} s^{- 1}$