According to Graham’s law, the rate of diffusion of CO, O2, N2 and CO2 follows the order

Question

According to Graham’s law, the rate of diffusion of CO, O2, N2 and CO2 follows the order (A) CO = N2 > O2 > CO2 (B) CO = N2 > CO2 > O2 (C) O2 > CO = N2 > CO2 (D) CO2 > O2 > CO = N2

Tardigrade Admin · Accepted Answer

According to Grahamâs law, rate of diffusion is inversely proportional to the square root of molar mass, i.e. r propto(1/√M) Thus, rate of diffusion decrease with increase in molecular weight. Therefore, the order of rate of diffusion will be CO = N2 > O2 > CO2 (28 g) (28 g) (32 g) (44 g)

Q. According to Graham’s law, the rate of diffusion of $CO, O_{2,} N_{2}$ and $C O_{2}$ follows the order

$CO = N_{2} > O_{2} > C O_{2}$

$CO = N_{2} > C O_{2} > O_{2}$

$O_{2} > CO = N_{2} > C O_{2}$

$C O_{2} > O_{2} > CO = N_{2}$

Q. According to Graham’s law, the rate of diffusion of CO,O2,​N2​ and CO2​ follows the order

CO=N2​>O2​>CO2​

CO=N2​>CO2​>O2​

O2​>CO=N2​>CO2​

CO2​>O2​>CO=N2​

According to Graham’s law, rate of diffusion is inversely proportional to the square root of molar mass, i.e. r∝M​1​ Thus, rate of diffusion decrease with increase in molecular weight. Therefore, the order of rate of diffusion will be CO=N2>O2​>CO2​ (28g)(28g)(32g)(44g)

Q. According to Graham’s law, the rate of diffusion of $CO, O_{2,} N_{2}$ and $C O_{2}$ follows the order

$CO = N_{2} > O_{2} > C O_{2}$

$CO = N_{2} > C O_{2} > O_{2}$

$O_{2} > CO = N_{2} > C O_{2}$

$C O_{2} > O_{2} > CO = N_{2}$