Where symbols have their usual meanings. According to equipartition law of energy each particle in a system of particles have thermal energy E equal to

Question

Where symbols have their usual meanings. According to equipartition law of energy each particle in a system of particles have thermal energy E equal to (A)  E=kBT (B)  E=(1/2)kBT  (C) E=3 kBT (D)  E=(3/2) kBT

Tardigrade Admin · Accepted Answer

From law of equipartition of energy for any system in thermal equilibrium, the total energy is equally distributed among its various degree of freedom and each degree of freedom is associated with energy

\frac{1}{2} k_{B} T

.

Q. Where symbols have their usual meanings. According to equipartition law of energy each particle in a system of particles have thermal energy $E$ equal to

$E = k_{B} T$

$E = (1/2) k_{B} T$

$E = 3 k_{B} T$

$E = (3/2) k_{B} T$

From law of equipartition of energy for any system in thermal equilibrium, the total energy is equally distributed among its various degree of freedom and each degree of freedom is associated with energy
$\frac{1}{2} k_{B} T$ .

Q. Where symbols have their usual meanings. According to equipartition law of energy each particle in a system of particles have thermal energy E equal to

E=kB​T

E=(1/2)kB​T

E=3kB​T

E=(3/2)kB​T