According to Einstein's photoelectric equation, the graph between the kinetic energy of photoelectrons ejected and the frequency of incident radiation is

Question

According to Einstein's photoelectric equation, the graph between the kinetic energy of photoelectrons ejected and the frequency of incident radiation is (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

According to Einstein equation h v=h v0+K max ⇒ K max =h v-h v0 on comparing it with y=m x+ c, it is clear to say that, This is the equation of straight line having positive slope (h) and negative intercept (h v0) on K E axis.

Q. According to Einstein's photoelectric equation, the graph between the kinetic energy of photoelectrons ejected and the frequency of incident radiation is

According to Einstein equation
$h v = h v_{0} + K_{m a x}$
$\Rightarrow K_{m a x} = h v - h v_{0}$
on comparing it with $y = m x + c$ ,
it is clear to say that,
This is the equation of straight line having positive slope $(h)$ and negative intercept $(h v_{0})$ on $K E$ axis.

Q. According to Einstein's photoelectric equation, the graph between the kinetic energy of photoelectrons ejected and the frequency of incident radiation is

According to Einstein equation hv=hv0​+Kmax​ ⇒Kmax​=hv−hv0​ on comparing it with y=mx+c, it is clear to say that, This is the equation of straight line having positive slope (h) and negative intercept (hv0​) on KE axis.

According to Einstein equation
$h v = h v_{0} + K_{m a x}$
$\Rightarrow K_{m a x} = h v - h v_{0}$
on comparing it with $y = m x + c$ ,
it is clear to say that,
This is the equation of straight line having positive slope $(h)$ and negative intercept $(h v_{0})$ on $K E$ axis.