Question

According to de Broglie concept, all material particles posses wave character as well as particle character. The wave associated with a moving particle is called matter wave. The wavelength of the matter wave is given by the equation
$\lambda =\frac{h}{p}=\frac{h}{mv}$ where $p$ is the momentum of the particle, ${}^{\prime }m$ ' is the mass of the particle and ' $v$ ' is the velocity of the particle. 'h' is called Planck's constant.
The wavelength associated with an electron (mass = $9.11\times 10^{-31}kg$ ) moving with a velocity of $10^{6}m{s}^{-1}$ is $\left(h=6.625\times 10^{-34}Js\right)$

• A. 0.727 nm
• B. 7.27 nm
• C. 727 nm
• D. 7.27 m

Answer 1

Answer: (A)

$\lambda =\frac{h}{mv}$
$=\frac{6.625\times 10^{-34}}{9.11\times 10^{-31}\times 10^6}$ meter
$=\frac{6.625}{9.11}\times 10^{-9}$ meter
$=0.727\times 10^{-9}$ metre
$=0.727nm$