Question

According to Bohr’s theory, the angular momentum for an electron of $3rd$ orbit is

• A. $3\hslash$
• B. $1.5\hslash$
• C. $9\hslash$
• D. $2\frac{\hslash }{\pi }$

Answer 1

Answer: (A)

Angular momentum, mvr
$=\frac{nh}{2\pi }=\frac{3\times h}{2\pi }=\frac{1.5h}{\pi }$
$=3\hslash \left[\because \hslash =\frac{h}{2\pi }\right]$