Acceleration due to gravity is g on the surface of the earth. Then the value of the acceleration due to gravity at a height of 32 km above earths surface is (Assume radius of earth to be 6400 km)

Question

Acceleration due to gravity is g on the surface of the earth. Then the value of the acceleration due to gravity at a height of 32 km above earths surface is (Assume radius of earth to be 6400 km) (A) 0.99 g (B) 0.8 g (C) 1.01 g (D) 0.9 g

Tardigrade Admin · Accepted Answer

g=(g/( 1+(h)Re )2) =(g/( 1+(32)6400 )2) =0.99 g

Q. Acceleration due to gravity is $g$ on the surface of the earth. Then the value of the acceleration due to gravity at a height of $32 km$ above earths surface is (Assume radius of earth to be $6400 km$ )

0.99 g

0.8 g

1.01 g

0.9 g

$g = \frac{g}{( 1 + \frac{h}{R _{e}} ) ^{2}}$
$= \frac{g}{( 1 + \frac{32}{6400} ) ^{2}}$
$= 0.99 g$

Q. Acceleration due to gravity is g on the surface of the earth. Then the value of the acceleration due to gravity at a height of 32km above earths surface is (Assume radius of earth to be 6400km)