Acceleration due to gravity is g on the surface of the earth. The value of acceleration due to gravity at a height of 32 km above earth's surface is (Radius of the earth =6400 km )

Question

Acceleration due to gravity is g on the surface of the earth. The value of acceleration due to gravity at a height of 32 km above earth's surface is (Radius of the earth =6400 km ) (A) 0.9 g (B) 0.99 g (C) 0.8 g (D) 1.01 g

Tardigrade Admin · Accepted Answer

h=32 km,R=6400 km , so h < < R gâ²=g(1 - (2 h/R))=g(1 - (2 × 32/6400)) ⇒ gâ²=(99/100)g=0.99 g

Q. Acceleration due to gravity is $g$ on the surface of the earth. The value of acceleration due to gravity at a height of $32 km$ above earth's surface is (Radius of the earth $= 6400 km$ )

$0.9 g$

$0.99 g$

$0.8 g$

$1.01 g$

$h = 32 km, R = 6400 km$ , so $h << R$
$g^{'} = g (1 - \frac{2 h}{R}) = g (1 - \frac{2 \times 32}{6400}) \Rightarrow g^{'} = \frac{99}{100} g = 0.99 g$

Q. Acceleration due to gravity is g on the surface of the earth. The value of acceleration due to gravity at a height of 32km above earth's surface is (Radius of the earth =6400km )

0.9g

0.99g

0.8g

1.01g