Question

Acceleration due to gravity is $g$ on the surface of the earth. The value of acceleration due to gravity at a height of $32 \, km$ above earth's surface is (Radius of the earth $=6400 \, km$ )

• A. $0.9 \, g$
• B. $0.99 \, g$
• C. $0.8 \, g$
• D. $1.01 \, g$

Answer 1

Answer: (B)

$h=32 \, km,R=6400 \, km$ , so $h < < R$
$g^{′}=g\left(1 - \frac{2 h}{R}\right)=g\left(1 - \frac{2 \times 32}{6400}\right) \, \, \Rightarrow \, \, g^{′}=\frac{99}{100}g=0.99 \, g$