AB crystallizes in a body centred cubic lattice with edge length ‘a’ equal to 387 pm. The distance between two oppositively charged ions in the lattice is

Question

AB crystallizes in a body centred cubic lattice with edge length ‘a’ equal to 387 pm. The distance between two oppositively charged ions in the lattice is (A) 300 pm (B) 335 pm (C) 250 pm (D) 200 pm

Tardigrade Admin · Accepted Answer

For BCC r++r-=(√3 a/2) r++r-=(√3 × 387/2)pm=335.14pm≈335pm

Q. AB crystallizes in a body centred cubic lattice with edge length ‘a’ equal to 387 pm. The distance between two oppositively charged ions in the lattice is

300 pm

335 pm

250 pm

200 pm

For BCC
$r^{+} + r^{-} = \frac{3 a}{2}$
$r^{+} + r^{-} = \frac{3 \times 387}{2} p m = 335.14 p m \approx 335 p m$

Q. AB crystallizes in a body centred cubic lattice with edge length ‘a’ equal to 387 pm. The distance between two oppositively charged ions in the lattice is

300 pm

335 pm

250 pm

200 pm

For BCC r++r−=23​a​ r++r−=23​×387​pm=335.14pm≈335pm

For BCC
$r^{+} + r^{-} = \frac{3 a}{2}$
$r^{+} + r^{-} = \frac{3 \times 387}{2} p m = 335.14 p m \approx 335 p m$