A Zener diode undergoes breakdown for an electric field of 106Vm- 1 at the depletion region of p - n junction. If the width of the depletion region is 2.5 textμm , what should be the reverse-biased potential for the breakdown to occur?

Question

A Zener diode undergoes breakdown for an electric field of 106Vm- 1 at the depletion region of p - n junction. If the width of the depletion region is 2.5 textμm , what should be the reverse-biased potential for the breakdown to occur? (A)  text3.5 textV (B)  text2.5 textV (C)  text1.5 textV (D)  text0.5 textV

Tardigrade Admin · Accepted Answer

Reverse biased potential for the zener breakdown Vr=Ed=106× 2.5× 10- 6=2.5 volt

Q. A Zener diode undergoes breakdown for an electric field of $1 0^{6} V m^{- 1}$ at the depletion region of $p$ - $n$ junction. If the width of the depletion region is $2.5 μm$ , what should be the reverse-biased potential for the breakdown to occur?

$3.5 V$

$2.5 V$

$1.5 V$

$0.5 V$

Reverse biased potential for the zener breakdown
$V_{r} = E d = 1 0^{6} \times 2.5 \times 1 0^{- 6} = 2.5$ volt

Q. A Zener diode undergoes breakdown for an electric field of 106Vm−1 at the depletion region of p - n junction. If the width of the depletion region is 2.5μm , what should be the reverse-biased potential for the breakdown to occur?

3.5V

2.5V

1.5V

0.5V