A zener diode in the circuit shown has a knee current of 5mA and a maximum allowed power dissipation of 300mW. What are the minimum and maximum load currents that can be drawn safely from the circuit, keeping the output voltage V0 constant at 6 volts ?

Question

A zener diode in the circuit shown has a knee current of 5mA and a maximum allowed power dissipation of 300mW. What are the minimum and maximum load currents that can be drawn safely from the circuit, keeping the output voltage V0 constant at 6 volts ? <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-yqrqeyvlimxxqpfb.jpg" /> (A) 0mA,180mA (B) 5mA,110mA (C) 10mA,55mA (D) 60mA,180mA

Tardigrade Admin · Accepted Answer

Current from source is I=(.9-6.)/50=.06A =60mA Now, Iz m i n=5mA and Iz m a x=Pm a x/Vz=300mW/6V=50mA So, Lm a x=I-Iz m i n=60mA-5mA=55mA And Lm i n=I-Iz m a x=60mA-50mA-50mA =10

Q. A zener diode in the circuit shown has a knee current of $5 m A$ and a maximum allowed power dissipation of $300 mW .$ What are the minimum and maximum load currents that can be drawn safely from the circuit, keeping the output voltage $V_{0}$ constant at 6 volts ?

$0 m A, 180 m A$

$5 m A, 110 m A$

$10 m A, 55 m A$

$60 m A, 180 m A$

Current from source is $I = (9 - 6) /50 = .06 A$
$= 60 m A$
Now, $I_{z min} = 5 m A$ and
$I_{z ma x} = P_{ma x} / V z = 300 mW /6 V = 50 m A$
So, $L_{ma x} = I - I_{z min} = 60 m A - 5 m A = 55 m A$
And $L_{min} = I - I_{z ma x} = 60 m A - 50 m A - 50 m A$
$= 10$

Q. A zener diode in the circuit shown has a knee current of 5mA and a maximum allowed power dissipation of 300mW. What are the minimum and maximum load currents that can be drawn safely from the circuit, keeping the output voltage V0​ constant at 6 volts ?

0mA,180mA

5mA,110mA

10mA,55mA

60mA,180mA