A YDSE is conducted in water (μ1) as shown in figure. A glass plate of thickness t and refractive index μ2 is placed in the path of S2. The optical path difference at O is

Question

A YDSE is conducted in water (μ1) as shown in figure. A glass plate of thickness t and refractive index μ2 is placed in the path of S2. The optical path difference at O is (A) (μ2-1) t (B) (μ1-1) t (C) ((μ2/μ1)-1) t (D) (μ2-μ1) t

Tardigrade Admin · Accepted Answer

Optical path difference Δ x=(μ2-μ1) t

Q. A YDSE is conducted in water $(μ_{1})$ as shown in figure. A glass plate of thickness $t$ and refractive index $μ_{2}$ is placed in the path of $S_{2}$ . The optical path difference at $O$ is

$(μ_{2} - 1) t$

$(μ_{1} - 1) t$

$(\frac{μ _{2}}{μ _{1}} - 1) t$

$(μ_{2} - μ_{1}) t$

Optical path difference
$Δ x = (μ_{2} - μ_{1}) t$

Q. A YDSE is conducted in water (μ1​) as shown in figure. A glass plate of thickness t and refractive index μ2​ is placed in the path of S2​. The optical path difference at O is

(μ2​−1)t

(μ1​−1)t

(μ1​μ2​​−1)t

(μ2​−μ1​)t