A wooden box is placed on a table. The normal force on the box from the table is N1. Now another identical box is kept on first box and the normal force on lower block due to upper block is N2 and normal force on lower block by the table is N3. For this situation, mark out the correct statement(s).

Question

A wooden box is placed on a table. The normal force on the box from the table is N1. Now another identical box is kept on first box and the normal force on lower block due to upper block is N2 and normal force on lower block by the table is N3. For this situation, mark out the correct statement(s). (A) N1=N2=N3 (B) N1 < N2=N3 (C) N1=N2 < N3 (D) N1=N2 > N3

Tardigrade Admin · Accepted Answer

Let the weight of each block be W (see figure) <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/cc91ebc93d4b51f3cd6bb2539ca2580a-.png" /> So, N1=N2=(N3/2)

$N_{1} = N_{2} = N_{3}$

$N_{1} < N_{2} = N_{3}$

$N_{1} = N_{2} < N_{3}$

$N_{1} = N_{2} > N_{3}$

Let the weight of each block be $W$ (see figure)

So, $N_{1} = N_{2} = \frac{N _{3}}{2}$

N1​=N2​=N3​

N1​<N2​=N3​

N1​=N2​<N3​

N1​=N2​>N3​

Let the weight of each block be W (see figure) So, N1​=N2​=2N3​​

$N_{1} = N_{2} = N_{3}$

$N_{1} < N_{2} = N_{3}$

$N_{1} = N_{2} < N_{3}$

$N_{1} = N_{2} > N_{3}$

Let the weight of each block be $W$ (see figure)

So, $N_{1} = N_{2} = \frac{N _{3}}{2}$