A woman (whose father is colour blind but mother is normal) marries a haemophiliac man with hypertrichosis. What percentage of progeny will show genotypically any two of the traits out of the three mentioned above at a given time?

Question

A woman (whose father is colour blind but mother is normal) marries a haemophiliac man with hypertrichosis. What percentage of progeny will show genotypically any two of the traits out of the three mentioned above at a given time? (A) 0 % (B) 25 % (C) 50 % (D) 75 %

Tardigrade Admin · Accepted Answer

Let Xc be the X chromosome with colourblindness gene, Xh be the X chromosome with haemophilia gene and Yt be the Y chromosome with hypertrichosis gene.
The woman receives on X chromosome from colourblind father and one X chromosome from a normal mother. Her genotype will be XXc. The man is heamophilic with hypertrichosis, so his genotype will be XhYt.
Their possible progenies will be

	Xh	Yt
X	XXh	XYt
Xc	XcXh	XcYt

Genotypically any two of the traits out of the three traits will be seen in XcXh and XcYt. Thus the answer is 50%

Q. A woman (whose father is colour blind but mother is normal) marries a haemophiliac man with hypertrichosis. What percentage of progeny will show genotypically any two of the traits out of the three mentioned above at a given time?

0 %

25 %

50 %

75 %