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Tardigrade
Question
Physics
A wire of resistance 3 Ω is stretched to twice its original length. The resistance of the new wire will be
Q. A wire of resistance
3
Ω
is stretched to twice its original length. The resistance of the new wire will be
7609
182
KCET
KCET 2021
Current Electricity
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A
1.5
Ω
7%
B
3
Ω
12%
C
6
Ω
27%
D
12
Ω
55%
Solution:
R
2
=
n
2
R
1
R
2
=
2
2
×
3
R
2
=
12
Ω