A wire of resistance 12 ohms per meter is bent to form a complete circle of radius 10 cm. The resistance between its two diametrically opposite points, A and B as shown in the figure is

Question

A wire of resistance 12 ohms per meter is bent to form a complete circle of radius 10 cm. The resistance between its two diametrically opposite points, A and B as shown in the figure is (A) 3 Ω (B) 6π Ω (C) 6 Ω (D) 0.6 π Ω

Tardigrade Admin · Accepted Answer

Total resistance of wire =12 Ω × 2 π × 10-1 =2.4 π Resistance of each half =(2.4 π/2)=1.2 π and as about diameter both parts are in parallel Req. =(1.2 π/2)=0.6 π Ω

Q. A wire of resistance $12$ ohms per meter is bent to form a complete circle of radius $10 c m$ . The resistance between its two diametrically opposite points, $A$ and $B$ as shown in the figure is

$3 Ω$

$6 π Ω$

$6 Ω$

$0.6 π Ω$

Total resistance of wire $= 12Ω \times 2 π \times 1 0^{- 1}$ $= 2.4 π$
Resistance of each half $= \frac{2.4 π}{2} = 1.2 π$
and as about diameter both parts are in parallel
Req. $= \frac{1.2 π}{2} = 0.6 π Ω$

Q. A wire of resistance 12 ohms per meter is bent to form a complete circle of radius 10cm. The resistance between its two diametrically opposite points, A and B as shown in the figure is

3Ω

6πΩ

6Ω

0.6πΩ