A wire of mass 100g is carrying a current of 2A in the form of y = x2 (-􏰅2 ≤ x ≤ 2). The wire is place 􏰆y in a magnetic field vecB = -0.02 hatk T The acceleration of wire in (m/s2) is (Neglect gravity and x and y are in metre)

Question

A wire of mass 100g is carrying a current of 2A in the form of y = x2 (-􏰅2 ≤ x ≤ 2). The wire is place 􏰆y in a magnetic field vecB = -0.02 hatk T The acceleration of wire in (m/s2) is (Neglect gravity and x and y are in metre) (A) −1.6 hat j (B) −3.2 hat j (C) −1.6 hat j (D) Zero

Tardigrade Admin · Accepted Answer

vecF =2[4 hati×(-0.02 hatk)]=0.16 hatj vecF = i( vecI× vecB) vecF =2[4 hati×(-0.02 hatk)]=0.16 hatj a =( vecF/m) = (0.16 hatj/100×10-3)=1.6 hatj m/s2

Q. A wire of mass 100g is carrying a current of 2A in the form of $y = x^{2} (- 􏰅2 \leq x \leq 2)$ . The wire is place 􏰆y in a magnetic field $B$ = $- 0.02 \hat{k} T$ The acceleration of wire in $(m / s^{2})$ is (Neglect gravity and x and y are in metre)

$- 1.6 \hat{j}$

$- 3.2 \hat{j}$

$- 1.6 \hat{j}$

Zero

$F = 2 [4 \hat{i} \times (- 0.02 \hat{k})] = 0.16 \hat{j}$
$F = i (I \times B)$
$F = 2 [4 \hat{i} \times (- 0.02 \hat{k})] = 0.16 \hat{j}$
$a = \frac{F}{m} = \frac{0.16 j ^}{100 \times 1 0 ^{- 3}} = 1.6 \hat{j} m / s^{2}$

Q. A wire of mass 100g is carrying a current of 2A in the form of y=x2(−􏰅2≤x≤2). The wire is place 􏰆y in a magnetic field B = −0.02k^T The acceleration of wire in (m/s2) is (Neglect gravity and x and y are in metre)

−1.6j^​

−3.2j^​

−1.6j^​

Zero

F=2[4i^×(−0.02k^)]=0.16j^​ F=i(I×B) F=2[4i^×(−0.02k^)]=0.16j^​ a=mF​=100×10−30.16j^​​=1.6j^​m/s2

Q. A wire of mass 100g is carrying a current of 2A in the form of $y = x^{2} (- 􏰅2 \leq x \leq 2)$ . The wire is place 􏰆y in a magnetic field $B$ = $- 0.02 \hat{k} T$ The acceleration of wire in $(m / s^{2})$ is (Neglect gravity and x and y are in metre)

$- 1.6 \hat{j}$

$- 3.2 \hat{j}$

$- 1.6 \hat{j}$

$F = 2 [4 \hat{i} \times (- 0.02 \hat{k})] = 0.16 \hat{j}$
$F = i (I \times B)$
$F = 2 [4 \hat{i} \times (- 0.02 \hat{k})] = 0.16 \hat{j}$
$a = \frac{F}{m} = \frac{0.16 j ^}{100 \times 1 0 ^{- 3}} = 1.6 \hat{j} m / s^{2}$