A wire of length 10 cm is placed horizontal on the surface of water and is gently pulled up with a force of 1.8× 10-2N to keep the wire in equilibrium. The surface tension of water will be

Question

A wire of length 10 cm is placed horizontal on the surface of water and is gently pulled up with a force of 1.8× 10-2N to keep the wire in equilibrium. The surface tension of water will be (A) 0.99 N/m (B) 0.09 N/m (C) 0.59 m (D) 59 N/m

Tardigrade Admin · Accepted Answer

T=(F/2l) =(1.8× 10-2/2× 10× 10-2) =0.09 N text/m

Q. A wire of length 10 cm is placed horizontal on the surface of water and is gently pulled up with a force of $1.8 \times 10^{- 2} N$ to keep the wire in equilibrium. The surface tension of water will be

0.99 N/m

0.09 N/m

0.59 m

59 N/m

$T = \frac{F}{2 l}$ $= \frac{1.8 \times 10 ^{- 2}}{2 \times 10 \times 10 ^{- 2}}$ $= 0.09 N / m$

Q. A wire of length 10 cm is placed horizontal on the surface of water and is gently pulled up with a force of 1.8×10−2N to keep the wire in equilibrium. The surface tension of water will be