A wire of length 1 m moving with velocity 8 m / s at right angles to a magnetic field of 2 T. The magnitude of induced emf, between the ends of wire will be

Question

A wire of length 1 m moving with velocity 8 m / s at right angles to a magnetic field of 2 T. The magnitude of induced emf, between the ends of wire will be  (A) 20 V (B) 16 V (C) 8 V (D) 12 V

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/87ca6ff6f96d359b87ece6f3a72a0593-.png" /> Induced emf across the ends = Bv ℓ =2 × 8 × 1=16 V

Q. A wire of length $1 m$ moving with velocity $8 m / s$ at right angles to a magnetic field of $2 T$ . The magnitude of induced emf, between the ends of wire will be ______

$20 V$

$16 V$

$8 V$

$12 V$

Induced emf across the ends $= B v ℓ$
$= 2 \times 8 \times 1 = 16 V$

Q. A wire of length 1m moving with velocity 8m/s at right angles to a magnetic field of 2T. The magnitude of induced emf, between the ends of wire will be ______

20V

16V

8V

12V