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Tardigrade
Question
Physics
A wire has resistance of 3.1 Ω at 30° C and 4.5 Ω at 100° C . The temperature coefficient of resistance of the wire is
Q. A wire has resistance of
3.1
Ω
at
3
0
∘
C
and
4.5
Ω
at
10
0
∘
C
. The temperature coefficient of resistance of the wire is
7349
237
TS EAMCET 2017
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A
0.001
2
∘
C
−
1
B
0.002
4
∘
C
−
1
C
0.003
2
∘
C
−
1
D
0.006
4
∘
C
−
1
Solution:
Given,
R
2
​
=
4.5Ω
R
1
​
=
3.1Ω
T
1
​
=
3
0
∘
C
T
2
​
=
10
0
∘
C
T
2
​
−
T
1
​
=
(
100
−
30
)
∘
C
=
7
0
∘
⇒
4.5
=
3.1
[
1
+
α
(
70
)]
⇒
70
α
=
3.1
4.5
​
−
1
α
=
3.1
×
70
4.5
−
3.1
​
α
=
6.45
×
1
0
−
3
α
=
0.006
4
∘
C
−
1