A white crystalline salt A reacts with dilute HCl to liberate a suffocating gas B and also forms a yellow precipitate. The gas B turns potassium dichromate acidified with dilute H2SO4 to a green coloured solution C, A, B and C are respectively

Question

A white crystalline salt A reacts with dilute HCl to liberate a suffocating gas B and also forms a yellow precipitate. The gas B turns potassium dichromate acidified with dilute H2SO4 to a green coloured solution C, A, B and C are respectively (A) Na2S2O3, SO2, Cr2(SO4)3 (B) Na2SO3, SO2, Cr2(SO4)3 (C) Na2SO4, SO2, Cr2(SO4)3 (D) Na2S, SO2, Cr2(SO4)3

Tardigrade Admin · Accepted Answer

Gas B turns the colour of acidified K 2 Cr 2 O 7 green thus it is SO 2 and SO 2 is obtained along with yellow precipitate when thio sulphate is treated with dilute acids. Thus, A is Na 2 S 2 O 3, B is SO 2 and C is Cr 2( SO 4)3. The reactions are as follows <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/7f62ebf1798dcd4b780637d95cb81f0d-.png" />

Q. A white crystalline salt $A$ reacts with dilute $H Cl$ to liberate a suffocating gas $B$ and also forms a yellow precipitate. The gas $B$ turns potassium dichromate acidified with dilute $H_{2} S O_{4}$ to a green coloured solution $C, A, B$ and $C$ are respectively

$N a_{2} S_{2} O_{3}, S O_{2}, C r_{2} (S O_{4})_{3}$

$N a_{2} S O_{3}, S O_{2}, C r_{2} (S O_{4})_{3}$

$N a_{2} S O_{4}, S O_{2}, C r_{2} (S O_{4})_{3}$

$N a_{2} S, S O_{2}, C r_{2} (S O_{4})_{3}$

Q. A white crystalline salt A reacts with dilute HCl to liberate a suffocating gas B and also forms a yellow precipitate. The gas B turns potassium dichromate acidified with dilute H2​SO4​ to a green coloured solution C,A,B and C are respectively

Na2​S2​O3​,SO2​,Cr2​(SO4​)3​

Na2​SO3​,SO2​,Cr2​(SO4​)3​

Na2​SO4​,SO2​,Cr2​(SO4​)3​

Na2​S,SO2​,Cr2​(SO4​)3​

Gas B turns the colour of acidified K2​Cr2​O7​ green thus it is SO2​ and SO2​ is obtained along with yellow precipitate when thio sulphate is treated with dilute acids. Thus, A is Na2​S2​O3​,B is SO2​ and C is Cr2​(SO4​)3​. The reactions are as follows

Q. A white crystalline salt $A$ reacts with dilute $H Cl$ to liberate a suffocating gas $B$ and also forms a yellow precipitate. The gas $B$ turns potassium dichromate acidified with dilute $H_{2} S O_{4}$ to a green coloured solution $C, A, B$ and $C$ are respectively

$N a_{2} S_{2} O_{3}, S O_{2}, C r_{2} (S O_{4})_{3}$

$N a_{2} S O_{3}, S O_{2}, C r_{2} (S O_{4})_{3}$

$N a_{2} S O_{4}, S O_{2}, C r_{2} (S O_{4})_{3}$

$N a_{2} S, S O_{2}, C r_{2} (S O_{4})_{3}$