A wheel whose moment of inertia is 2 kg m2 has an initial angular velocity of 50 rad s-1. A constant torque of 10 N m acts on the wheel. The time in which the wheel is accelerated to 80 rad s-1 is

Question

A wheel whose moment of inertia is 2 kg m2 has an initial angular velocity of 50 rad s-1. A constant torque of 10 N m acts on the wheel. The time in which the wheel is accelerated to 80 rad s-1 is (A) 12 s (B) 3 s (C) 6 s (D) 9 s

Tardigrade Admin · Accepted Answer

Initial angular velocity = 50 rad s-1. Final angular velocity = 80 rad s-1, Torque = 10 N m Moment of inertia =2 kg m2 Angular acceleration α is given by τ = I α α = (τ/I) = (10/2) = 5 rad s-2 Hence if t is the time, 5t = 80 -50 = 30 : :: ⇒ : : t = 6 s

Q. A wheel whose moment of inertia is 2kgm2 has an initial angular velocity of 50rads−1. A constant torque of 10 N m acts on the wheel. The time in which the wheel is accelerated to 80rads−1 is

12 s

3 s

6 s

9 s

Initial angular velocity = 50rads−1. Final angular velocity = 80rads−1, Torque = 10Nm Moment of inertia =2kgm2 Angular acceleration α is given by τ=Iα α=Iτ​=210​=5rads−2 Hence if t is the time, 5t=80−50=30⇒t=6s

Q. A wheel whose moment of inertia is $2 k g m^{2}$ has an initial angular velocity of $50 r a d s^{- 1}$ . A constant torque of 10 N m acts on the wheel. The time in which the wheel is accelerated to $80 r a d s^{- 1}$ is