A wheel starts from rest and attains an angular velocity of 20 radian/s after being uniformly accelerated for 10 s. The total angle in radian through which it has turned in 10 second is

Question

A wheel starts from rest and attains an angular velocity of 20 radian/s after being uniformly accelerated for 10 s. The total angle in radian through which it has turned in 10 second is (A) 20 π (B) 40 π (C) 100 (D) 100 π

Tardigrade Admin · Accepted Answer

ωf=ωl+α t 20=0+α(10) α=2 rad / s 2 Now, θ=ωi t+(1/2) α t2 θ =(1/2)(2)(100) =100 radian

Q. A wheel starts from rest and attains an angular velocity of $20$ radian/s after being uniformly accelerated for $10 s$ . The total angle in radian through which it has turned in $10$ second is

$20 π$

$40 π$

$100$

$100 π$

$ω_{f} = ω_{l} + α t$
$20 = 0 + α (10)$
$α = 2 r a d / s^{2}$
Now, $θ = ω_{i} t + \frac{1}{2} α t^{2}$
$θ = \frac{1}{2} (2) (100)$
$= 100$ radian

Q. A wheel starts from rest and attains an angular velocity of 20 radian/s after being uniformly accelerated for 10s. The total angle in radian through which it has turned in 10 second is

20π

40π

100

100π